5[2t+1]+3[t+2]=

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Solution for 5[2t+1]+3[t+2]= equation:


Simplifying
5[2t + 1] + 3[t + 2] = 0

Reorder the terms:
5[1 + 2t] + 3[t + 2] = 0
[1 * 5 + 2t * 5] + 3[t + 2] = 0
[5 + 10t] + 3[t + 2] = 0

Reorder the terms:
5 + 10t + 3[2 + t] = 0
5 + 10t + [2 * 3 + t * 3] = 0
5 + 10t + [6 + 3t] = 0

Reorder the terms:
5 + 6 + 10t + 3t = 0

Combine like terms: 5 + 6 = 11
11 + 10t + 3t = 0

Combine like terms: 10t + 3t = 13t
11 + 13t = 0

Solving
11 + 13t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 13t = 0 + -11

Combine like terms: 11 + -11 = 0
0 + 13t = 0 + -11
13t = 0 + -11

Combine like terms: 0 + -11 = -11
13t = -11

Divide each side by '13'.
t = -0.8461538462

Simplifying
t = -0.8461538462

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